In the circuit, R = 26.0 kohms and C = 0.10 碌F. The capacitor is allowed to charge fully and then the switch is changed from position a to position b. What will the voltage across the resistor be 9.8 ms later?

90V is on the left of the box and directly across the box on the other side is C. R is on the top right side of the box (C side)What will the voltage across the resistor be 9.8 ms later? ?

Then you have a resistor and a fully charged(V=90) capacitor in series;

V(resistor)=90e^ [-(9.8/RC)],RC=26x10^3x0.1x10^-6=2.6msec鈥?br>

V(resistor)=90e^(-3.77)=2.0746856volts鈥?volts ,roughly.

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